How to make the number of gaps in the replacement equal to the length of the word or do a recalculation so that the replacement does not collapse?

Question

Java

Good afternoon!
It is necessary to replace with emptiness / remove words from the array in the string.
I find the initial indexes, and then I replace it with a void, but my replacements distort the text - how can I fix this?

ublic class Keywords {
    public static String searchAndReplaceKeywords(String afterD){
        String codeAfterSC="";
        Lexemes instanceLexemes = new Lexemes();
        StringInStringSearch instanceSearch = new StringInStringSearch();
        StringBuilder builder=new StringBuilder(afterD);
        for (int i = 0; i < instanceLexemes.stringKeywords.length; i++) {
            String word = instanceLexemes.stringKeywords[i];
            int size=word.length();
            System.out.println("Keyword :     " + word + "  finded in places: " + instanceSearch.findString(afterD, word));
            List<Integer> list=instanceSearch.findString(afterD, word);
            for(int j=0;j< list.size();j++){
                int indexDelete=list.get(j);
                int end=indexDelete+size;
                builder.replace(indexDelete,end,"    ");
            }
        }
        return codeAfterSC=builder.toString();

    }
}

Thank you.

Answer 1

Expand the loop where you iterate (j) over the occurrences of the keyword. If to delete from the end indexes will not move out.