How to make the bot wait for a message?

Question

Python

How to make the bot wait for the user to enter the task number, and then throw this value into the per variable?

def subject(message):
    if message.text == 'Русский язык':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True, one_time_keyboard=False)
        keyboard.row('Назад')
        send = bot.send_message(message.from_user.id, "2 уровень", reply_markup=keyboard)
        bot.register_next_step_handler(send, back)
    elif message.text == 'Алгебра':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True, one_time_keyboard=False)
        keyboard.row('Назад')
        send = bot.send_message(message.from_user.id, "2 уровень", reply_markup=keyboard)
        bot.register_next_step_handler(send, back)
    elif message.text == 'Физика':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True, one_time_keyboard=False)
        keyboard.row('Назад')
        send = bot.send_message(message.from_user.id, "2 уровень", reply_markup=keyboard)
        bot.register_next_step_handler(send, back)
    elif message.text == 'Русский язык':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True, one_time_keyboard=False)
        keyboard.row('Назад')
        send = bot.send_message(message.from_user.id, "text", reply_markup=keyboard)
        bot.register_next_step_handler(send, back)
    elif message.text == 'Геометрия':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True, one_time_keyboard=False)
        #keyboard.row('Ввести номер задания')
        keyboard.row('Назад')
        send = bot.send_message(message.from_user.id, "Введите номер задания", reply_markup=keyboard)
        bot.register_next_step_handler(send, geom)
    elif message.text == 'Домой':
        first(message)
def geom(message):
    listnum = range(1, 851)
    if message.text in listnum:
        per = str(message)
        URL = 'https://megaresheba.ru/gdz/geometriya/8-klass/merzlyak/' + per + '-nomer'
        print(URL)
        HEADERS = {
            'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/85.0.4183.83 Safari/537.36',
            'accept': '*/*'}

        def get_html(url, params=None):
            r = requests.get(url, headers=HEADERS, params=params)
            return r

        imgg = ''

        def get_content(html):
            global imgg
            soup = BeautifulSoup(html, 'html.parser')
            div = soup.find('div', {'class': 'with-overtask'})
            imgg = div.find('img')['src']
            return imgg

        def parse():
            html = get_html(URL)
            if html.status_code == 200:
                get_content(html.text)
            return html
        parse()
        print(imgg)

def back(message):
    if message.text == 'Назад':
        keyboard = types.ReplyKeyboardMarkup(resize_keyboard=True)
        keyboard.add(*[types.KeyboardButton(name) for name in ['Физика', 'Алгебра', 'Русский язык']])
        keyboard.add(*[types.KeyboardButton(name) for name in ['нет', 'да']])
        keyboard.add(*[types.KeyboardButton(name) for name in ['Домой']])
        send = bot.send_message(message.from_user.id, "2 уровень", reply_markup=keyboard)
        bot.register_next_step_handler(send, subject)
    print('hi')


if __name__ == '__main__':
    bot.polling(none_stop=True)

Answer 1

So message.textwhat do you have?

Answer 2

In such situations, I do this:
You create a database, in it the user ID and the menu cell
Next, there is a check,

if menu == 'change':
    if message.text == 'алгебра':
        ...
    else:
        send('неправильный выбор')