How to make such a redirect using the Apache configuration?

Question

Apache HTTP Server

Good day, I am making the Ajax site friendly for search engines.
Through .htaccess I'm trying to make the url of this type:
https://toster.ru/?_escaped_fragment_=/about/
Turn into this:
https://toster.ru/snapshot/about/
Wise-wise, and got this config:

RewriteEngine On
Options +FollowSymLinks
RewriteCond %{REQUEST_URI}  ^/$
RewriteCond %{QUERY_STRING} ^_escaped_fragment_=/?(.*)$
RewriteRule ^(.*)$ /snapshots/%1? [NC,L]

But it doesn't work

Answer 1

[NC,R=301,L]
to the last line