How to make gulp copy only new photos?

Question

JavaScript

The assembly copies all the photos first each time. And what I had

gulp.task('assets', function() {
  return gulp.src(['frontend/assets/{fonts,images}/**', 'frontend/assets/index.html'], {since: gulp.lastRun('assets')})
    .pipe(newer('public'))
    .pipe(gulp.dest('public'));
});

had to copy only what has changed. But for some reason it didn't work.
Is it possible to do something so that when adding photos, they themselves are copied as they are now, but not all, but only new ones?
Here is my task now:

gulp.task('assets', function() {
  return gulp.src('frontend/assets/{fonts,images}/**/*.*')
    .pipe(gulp.dest('public'));
});

Answer 1

Try gulp-changed
Works well