How to make an import.xml file parser?

Question

go

There is a file called import.xml. The file is located on the server where the site is located. There is a code that parses an external resource file. Question: How to parse a file that is on the server?
Here is the code to parse the file by reference.

func DownloadAzertiFile(url string) *AzertiCatalog {
  list := AzertiCatalog{}
  response, err := http.Get(url)
  if err != nil {
    return &list
  } else {
    defer response.Body.Close()
    body, _ := ioutil.ReadAll(response.Body)
    if err != nil {
      return &list
    }
    newbody := strings.Replace(string(body), "<offers>", "", -1)
    newbody = strings.Replace(newbody, "</offers>", "", -1)
    err := xml.Unmarshal([]byte(newbody), &list)
    if err != nil {
      return &list
    }
  }
  return &list
}

Answer 1

Good afternoon!

b, err := ioutil.ReadFile("path/to/file.xml")
if err != nil {
    panic(err
}

In b you will have the contents of the file as an array of bytes, which can be parsed by xml.Unmarshal as in your example