How to make a url from two slugs?

Question

Django

There are category and product models. It is necessary that the product url consists of a category slug and its own slug. This should look like 'category/slug category/product slug/'.

models.py

class Category(models.Model):
    title = models.CharField(max_length=155, verbose_name='Название категории')
    icon = models.ImageField(upload_to='img/category', blank=True, null=True, verbose_name='Картинка категории')
    slug = models.SlugField(unique=True, verbose_name='Слаг категории')

    def get_absolute_url(self):
        return reverse('category', kwargs={"slug": self.slug})

    def __str__(self):
        return self.title


class Product(models.Model):
    title = models.CharField(max_length=155, verbose_name='Название товара')
    description = models.TextField(blank=True, verbose_name='Описание товара')
    price = models.IntegerField(blank=True, verbose_name='Цена')
    category = models.ForeignKey('Category', on_delete=models.CASCADE)
    icon = models.ImageField(upload_to='img/product/%m', verbose_name='Картинка товара')
    slug = models.SlugField(unique=True, verbose_name='Адрес товара')

    def get_absolute_url(self):
        return reverse('product', kwargs={"slug": self.slug})

    def __str__(self):
        return self.title

urls.py

from django.urls import path
from . views import *


urlpatterns = [
    path('', home, name='home'),
    path('register/', user_register, name='register'),
    path('logout/', user_logout, name='logout'),
    path('login/', user_login, name='login'),
    path('category/<str:slug>/', CategoryList.as_view(), name='category'),
    path('<str:category>/<str:slug>/', ProductDetail.as_view(), name='product'),
]

views.py

class CategoryList(ListView):
    model = Product
    template_name = 'categories.html'
    context_object_name = 'items'
    paginate_by = 10
    allow_empty = False

    def get_queryset(self):
        return Product.objects.filter(category__slug=self.kwargs['slug'])

    def get_context_data(self, *, object_list=None, **kwargs):
        context = super().get_context_data(**kwargs)
        context['title'] = Category.objects.get(slug=self.kwargs['slug'])
        return context


class ProductDetail(DetailView):
    model = Product
    template_name = 'product.html'
    context_object_name = 'item'