How to make a request in django?

Question

Django

For example, there are two models Manager and Message.

class Manager(models.Model):
    name = models.CharField(max_length=255)
    create = models.DateTimeField(auto_now_add=True)

class Message(models.Model):
    text = models.TextField()
    manager = models.ForeignKey(Manager, models.SET_NULL, null=True)

You need to display the last 5 Managers created and each of them's messages.
How can it be done that in the template to use one object?
Or you must first get the Manager in the view

Managers = Manager.objects.all().order_by('-create')[:5]

And then, using the cycle, make a request
Messages = Enc.objects.filter(manager=Managers[i])
B somehow try to combine it into one object or list, so that later it can be output into a template in cycles.
Is there an easier way?

Answer 1

This is of course not the case, but it's better to format the code using tags.
Modify the message model like this:

class Message(models.Model):
  text = models.TextField()
  manager = models.ForeignKey(Manager, models.SET_NULL, null=True, related_name="messages")

By applying the migration, you will be able to access messages from the manager model. For example like this:

somemanager=Manager.objects.first()
messages=somemanager.messages

Well, then output this already in the template as you need