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How to make a C program that will ask the user for an integer [0;99] and display it in words on the screen?
You need to write a program that asks the user for an integer [0..99] and then displays the number in words on the screen. And if the user entered an incorrect number, then the program should ask you to enter a number from this range again.
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Something like this, but I'm tired of writing, I'll go to sleep
int main(void)
{
int x = -1;
char one[4] = "один";
char two[3] = "два";
char three[3] = "три";
char fout[6] = "четыре";
char five[4] = "пять";
char six[5] = "шесть";
char seven[4] = "семь";
char eight[6] = "восемь";
char nine[6] = "девять";
char tenPlus[6] = "надцать";
char tventy[8] = "Двадцать";
while(x < 0 || > 99)
{
printf("Введите число:\n");
scanf("%d", &x);
if(x < 0 || x > 99) printf("Введите число от 0 до 99:\n");
}
switch(x)
{
//логика
}
}
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