How to loop through all the elements of a bash array?

Question

bash

Good afternoon.
Given:
There is an array ${users[@]} - it consists of usernames, users 20.
There is such a command (connects to the database,
mysql -u root -p`cat .mysqlpasswdfile` -e "CREATE USER 'user '@'localhost' IDENTIFIED BY 'user'"
Question:
Please tell me how to write an expression so that at each pass of the loop the name from the array is substituted, moreover, each time a new one, and so on until the last name.