How to loop the result of a bash command?

Question

bash

There is a command that gives a list of Docker container names.
What is the correct way to write a loop in Bash?
How to substitute these names in a loop by executing another command?
Well, or maybe your options, the best ways to get the result of the team.

container=$(docker container ls --format 'table {{.Names}}');

  while $container
  do
    docker exec -u root -it $container netstat -natu | grep -c ESTABLISHED;
  done

Answer 1

To pass command output arguments as a single value, you need to have the correct output. Those. instead of

container=$(docker container ls --format 'table {{.Names}}')

gotta do

container=$(docker container ls --format '{{.Names}}')

In the end it should look something like this:

#!/bin/bash
container=$(docker container ls --format '{{.Names}}');

 for i in $container
 do
    docker exec -u root -it $i netstat -natu | grep -c ESTABLISHED;
 done