How to link menu and content in Django?

Question

Django

class Menu_bot_level(models.Model):
    bot_level_order = models.IntegerField()
    bot_level_name = models.CharField(max_length=255)
    bot_level_url = models.CharField(max_length=255)

class Menu_bot_mid_level(models.Model):
    bot_mid_level_fkb_id = models.ForeignKey('Menu_bot_level')
    bot_mid_level_order = models.IntegerField()
    bot_mid_level_name = models.CharField(max_length=255)
    bot_mid_level_url = models.CharField(max_length=255)

class Content(models.Model):
    url_link_m = models.ManyToManyField('Menu_bot_level', blank=True)
    url_link_bm = models.ManyToManyField('Menu_bot_mid_level', blank=True)
    title = models.CharField(max_length=200)
    text = models.TextField()

How do I bind the bot_level_url field and bot_mid_level_url for Content ?
In the admin panel, connect bot_level_url and bot_mid_level_url so that when you select a menu, open your content?