How to intercept file being processed in gulp?

Question

JavaScript

Actually, subject. The meaning is this: the galpa task is running, how can I intercept the file or get its url (I want to write it down in locals jade in order to pass it to jade templates)?

Answer 1

If you need to throw data into the template, then gulp-data . It would be more interesting for me to get a tree of all extends and include files, for example, to take data from _nav.jade.json, which, as it were, does not participate in compilation.

var getJadeDependencies = function (file) {
    return require(`jade`).compileFile(file).dependencies;
};

But there is no time yet, and there is not enough knowledge in JS.

Answer 2

If I understand correctly: hang after gulp.src gulp-filenames , then at the end of the stream, run the jade bundle with the entire list of files from the stream.
Offtopic:
Personally, I use this pattern: there is a certain json file into which I throw everything that I may need at the same time in js, jade or stylus, and then I pull it apart through locals (jade gult), require (js babel) and json ( style).