How to implement multithreading and exceptions?

Question

Python

Let's say we have the following code:

import re

from urllib2 import urlopen

startId = 5700
finalId = 6300

count = 0
totalWins = 0

pattern = "title=\'Fir\-tree defense\. Victories\: ([0-9]{1,2})"

for Id in range(startId, finalId):
    print Id
    try:
        u = urlopen("http://site.com/pl.php?id="+str(Id))
        data = u.read()
        arr = re.findall(pattern, data)
        if (len(arr) != 0):
            count = count + 1
            totalWins = totalWins + int(arr[0])
            print Id, " ", arr[0]
    except:
        Id = Id - 1

    

print "Total players involved: ", count
print "Total wins: ", totalWins

u.close()

Will it reload the page if it didn't load the first time?
How to make multithreading for this program?

Answer 1

Use Grab . It is more functional and in the settings you can specify how many times to try to open the site with different errors.
Copes with multithreading with a bang.

Answer 2

And how to solve this problem without the help of a third-party library?

Answer 3

If you want to repeat an action until it completes without throwing an exception, then you need to run an additional nested loop. In it, do break on else at the try construct. + here you can easily make a limited number of attempts.
p.s. catching exceptions without specifying the exception type is a very bad practice