How to handle requests like localhost:5000/foo?id=1?

Question

Flask

Greetings.
There is a certain table formed by flask-table, in the table there is a column with link generation
url = LinkCol('Details', 'foo', url_kwargs=dict(id='id') ,attr='name').

It creates links like localhost:5000/foo?id=1
How do I let python know that I requested an id of 1?

Answer 1

flask.pocoo.org/docs/0.12/quickstart/#the-request-...