How to group nested array elements by heading?

Question

JavaScript

There is an array: And another array:
var ind = ["Apple", "Pear", "Banana"];

let arr = [
  [ "Pear",        12,       34,     54,     76,      23,      232    ],
  [ "Apple",      54,       22,     11,     23,      21,      33      ],
  [ "Banana",   54,       65,     11,     43,      66,      75      ],
  [ "Pear",        23,       11,     46,     76,      33,      98      ],
  [ "Apple",      12,       34,     54,     76,      23,      232    ],
  [ "Banana",   54,       22,     11,     23,      21,      33      ],
];

How to concatenate all subarray values ​​in order as they go in ind array to do it like this:

let arr = [
  ["Apple",    [54,12], [22,34], [11,54], [23,76], [21,23], [33,232]],
  ["Pear",      [12,23], [34,11], [54,46], [76,76], [23,33], [232,38]],
  ["Banana", [54,54], [65,22], [11,11], [43,23], [66,21], [75,33 ]]
];

That is, first combine the values ​​​​of arrays into subarrays, into a cat. the first value is Apple, then Pear, then Banana. Like in an array var ind = ["Apple", "Pear", "Banana"];
The result may be as above, it may be as below:

let arr = [
  ,
  ,
  
];

It is highly desirable without things like Spread syntax (...) and Object.values(), since it needs to work at least in the latest ie

Answer 1

ind.map(((data, n) => data[n]).bind(null, arr.reduce((acc, row) => {
  const d = acc[row[0]];
  row.forEach((n, i) => i && (d[i] = d[i] || []).push(n));
  return acc;
}, ind.reduce((acc, n) => (acc[n] = [ n ], acc), {}))))