How to group data from another django model?

Question

Django

Good day, wise ones! There are models Protocol, Applicant, Type of assistance. The applicant is tied to a specific protocol and in turn to a specific type of assistance. Through the slug we get the page of a specific protocol, and the applicants related to this protocol. It is necessary to display a list of applicants grouped by type of assistance. The output should be like this:
1. Material:
-applicant;
- the applicant;
2. Pat on the shoulder:
-applicant;
- the applicant;
models.py

class Protocol(BaseModel):
    """Протокол"""
    title = models.CharField(
        _('Название'), max_length=255, db_index=True, blank=True,
        help_text=_('Обязательное поле')
    )
    slug = models.SlugField(
        _('Алиас'), max_length=150, db_index=True, unique=True,
        help_text=_('Латинские буквы и цифры')
    )
    date = models.DateTimeField(_('Дата протокола'), default=utcnow)

    class Meta:
        verbose_name = _('Протокол')
        verbose_name_plural = _('Протоколы')

    def __str__(self):
        return self.title


class HelpType(BaseModel):
    """Тип помощи"""
    title = models.CharField(
        _('Название'), max_length=255, db_index=True, blank=True,
        help_text=_('Обязательное поле')
    )

    class Meta:
        verbose_name = _('Тип помощи')
        verbose_name_plural = _('Типы помощи')

    def __str__(self):
        return self.title


class Applicant(BaseModel):
    """Заявитель"""
    name = models.CharField('ФИО', max_length=255, help_text=_('Обязательное поле'))
    position = models.CharField('Должность', max_length=255, null=True, blank=True)
    cause = models.CharField('Причина', max_length=255, null=True, blank=True)
    in_fond = models.CharField('Время пребывания в фонде', max_length=255, null=True, blank=True)
    summ = models.IntegerField('Сумма ходатайства', null=True, blank=True)
    summ_text = models.CharField('Сумма ходатайства прописью', max_length=255, null=True, blank=True)
    protocol = models.ForeignKey(
        'Protocol', verbose_name=(_('Протокол')), related_name='applicants', on_delete=models.CASCADE,
        blank=True, null=True
    )
    help_type = models.ForeignKey(
        'HelpType', verbose_name=(_('Тип помощи')), related_name='applicants', on_delete=models.CASCADE,
        blank=True, null=True
    )

    class Meta:
        verbose_name = 'Заявитель'
        verbose_name_plural = 'Заявители'
        ordering = ('ordering',)

    def __str__(self):
        return self.name

views.py:

class ProtocolView(BaseTemplateView):
    """Страница протокола"""
    template_name = 'protocols/protocol.html'

    def get_context_data(self, **kwargs):
        kwargs = super(ProtocolView, self).get_context_data(**kwargs)
        current_page = get_object_or_404(
            models.Protocol.objects.published(), slug__exact=kwargs.get('slug')
        )
        applicants = models.Applicant.objects.published().filter(protocol=current_page.pk)

        kwargs.update(
            current_page=current_page,
            applicants=applicants,
        )
        return kwargs

Answer 1

Briefly: sort the list of applicants by type of assistance and use the groupby tag in the template