How to get the values ​​of an array with a regular expression?

Question

Java

\\"bla\\":\[(?:\\"(\d+)\\",?)+\]


//\"bla\":[\"1000\",\"1002\",\"1\",\"22222\",\"333\",\"3333\",\"33344\"]

Matcher matcher = pattern.matcher(str);
if (matcher.find()) {
    System.out.println(matcher.group(1));
}

split do not offer

Answer 1

I don't think it's possible. It is easier and clearer to do it in two steps, first extract the contents of
"bla" from the square brackets:\[([^\]]*)\]
And then from the found contents of the square brackets get all the groups
"([0-9]+)"

String input = "\"bla\":[\"1000\",\"1002\",\"1\",\"22222\",\"333\",\"3333\",\"33344\"]";
        Pattern pattern = Pattern.compile("([0-9]){1,}");
        Matcher matcher = pattern.matcher(input.replaceAll("\"bla\":\\[([^\\]])\\]", "$1"));
        while (matcher.find()) {
            System.out.println("g:"+ matcher.start() + " " + matcher.group());
        }

And if you do not advise split, then it's probably easier to use gson. There you can bypass the json structure and get an array without reinventing the wheel and not necessarily