How to get the desired regexp result by pattern from text, not bool?

Question

go

Given text:
`From:` <@317989885321674753>
`To:` <@163995016027439106>
`Reason:` <@!163995016027439106> ....
You need to use regular expressions to get from it only the first one similar to "317989885321674753" it's just some ID is always the same length (18) and always digits.
Thank you!

Answer 1

Like this:
https://play.golang.org/p/cPnYojRRPP3

package main

import (
  "fmt"
  "regexp"
)

func main() {
  text := "`От:` <@317989885321674753>\n`На:` <@163995016027439106>\n`Причина:` <@!163995016027439106>"

  re := regexp.MustCompile(`\<\@\!?(\d{18})\>`)
  matches := re.FindAllStringSubmatch(text, -1)
  for _, match := range matches {
    if len(match) > 1 {
      fmt.Println(match[1])
    }
  }
}

Answer 2

https://golang.org/pkg/regexp/#example_Regexp_Find...