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20strannik082018-10-21 10:38:43
Do it yourself
20strannik08, 2018-10-21 10:38:43

How to get rid of the voltage drop on the transistor key under load?

There is a TIP42 transistor. If you apply 5V power to the base of this transistor through a 1K resistor, it opens and provides power. But under a load of 1 ampere (which this transistor opens), the voltage drops from 5.20 to 4.85 volts. How to overcome subsidence or is it better to replace this transistor with something else? (everything is soldered with thick wires, the problem of current drawdown is not in the wires)
The consumer will sit at 5V and consume current abruptly from 1A to 2.65A. It is necessary that 5V be confidently supplied through the transistor key

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2 answer(s)
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longclaps, 2018-10-21
@20strannik08

TIP42 is a type of transistor package. What's inside is a mystery.
If there is an ordinary bipolar transistor, and at a base current of 4.4mA it gives out 1A with a voltage drop of 0.35V - this is an excellent transistor. But for your task, a CMOS key is
better suited .

Z
ZloY_SemeN, 2018-10-24
@ZloY_SemeN

in general, for the TIP42 transistor, the case type is TO-220.
but otherwise I agree with you

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