How to get PMK from bssid of access point and password on your knee?

Question

Python

There is a BSSID and a password (let's say 12345678) you need to get a PMK from them.
from what I found, little sense:

PMK in WPA2
WPA2-Personal mode generates a 256-bit key, sometimes referred to as a PreShared Key (PSK), from the passphrase entered in plain text. After that, the PMK mathematical basis is generated from the PSK key, the SSID indicator (Service Set Identifier) ​​and its length.

It all starts with the "short password" (from the user) being converted into a longer key with the addition of the name of the wireless network - PBKDF is used for this, which can be equated to computing a hash over SHA-1 4096 times in a row. As a result, we get 256- bit string, i.e. 32 bytes. Note that it is unique for different networks with the same passwords if they have different names.

Pyrit has a batch command, which I wanted to deal with in python. If I understand correctly, then this command calculates the PMK from ssid + password, a database is created, which is then checked against handshake.
I found blocks on the pyrit github that mention sha and the number 4096, but I couldn’t figure it out.
Please, explain by what rules how the value is created {in pyrit}, which is then compared with the value obtained from HANDSHAKE.
Experience is expected:
1) generating a value (pmk) from Bssid ("d-link") and password ("12345678")
2) intercepting the handshake and comparing the value from the handshake with the generated value
3) confirming their equivalence