How to get a random number in a range with exceptions?

Question

Python

For example, in python there is a function randint(min, max), which gives a random number in the range from min to max.
I need a function that will take an array of exceptions: randint_se(min, max, exceptions), where exceptions is an array of those numbers that should not fall into the range. The exceptions array can be of any length.

Answer 1

I thought and solved the problem. Maybe someone will come in handy.

import random

def randint_se(min, max, exceptions):

  possible = []
  exceptions.sort()

  for number in range(min, max+1):
    count = 0
    for exception_number in exceptions:
      if number == exception_number:
        break
      count += 1
    if count == len(exceptions):
      possible.append(number)


  return random.choice(possible)

Answer 2

My take is
to adjust the maximum value to take into account the lengths of all excluded ranges, get a random number for the updated range, and then apply the list of excluded ranges to adjust the value.
Example: given to return a number from 1 to 6 (dice), but the number 4 is considered forbidden.
Solution: get a random number from 1 to 5 and if it is greater than and equal to 4, add to the result 1 (the length of the excluded range).