How to generate path to save file dynamically, DJANGO?

Question

Django

Here is the code

def upload_video(request):

      v = Video(video = request.FILES['videoFile'])
      v.safe()

class Video(models.Model):
     video = model.FileField(upload_to="/path/")

The problem is that the path to save the file needs to be generated dynamically, how can this be done

Answer 1

At least there is this
https://docs.djangoproject.com/en/dev/ref/models/f...
username/time/

import os
import datetime


def user_directory_path(instance, filename):
    # file will be uploaded to MEDIA_ROOT/user_<id>/<filename>
    return os.path.join(
               instance.user.name, 
               datetime.datetime.now().strftime('%Y_%m_%d__%H_%M'), 
               filename)


class MyModel(models.Model):
    upload = models.FileField(upload_to=user_directory_path)