How to find the minimum natural divisor of a number x?

Question

Python

Good evening!
Can you please tell me how to find the minimum natural divisor of a number x other than 1, i.e. y> 1?
For example, if the input is the number x=10, then y=2

Answer 1

Isn't this a very simple question? Obviously, you just need to divide cyclically by numbers, starting with 2, and check whether they divide the original number.

for i in range(2, x+1):
    if not x % i:
        print(i)
        break

If the number is large, then it is better to stop the loop at the root of x:

import math
for i in range(2, int(math.sqrt(x))+1):
    if not x % i:
        print(i)
        break
else:
    print(x)