How to find the following-sibling AND the node itself?

Question

XPath

Hello!

<root>
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li><div><a>6</a></div></li>
<li>7</li>
<li>8</li>
</root>

How in this code to find all the nodes before the node li/div/aAND the node itself from which we start ( li/div/a)?

Should return:

<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li><div><a>6</a></div></li>

Tried like this:

//li[div/a]/self::node()[self::node() and self::node()/preceding-sibling::li]

Doesn't work for some reason. Although it should.

Thank you!

Answer 1

You have an error in the title of your question. following is after the node. The correct expression would be:
//li[div/a]/(preceding-sibling::li|self::li)
If there is any misunderstanding in this expression, then ask. I can explain at each step of addressing.
There is a desire to understand XPath deeper, then I recommend an introductory video: XPath is strong!