How to find the always correct statement?

Question

go

How to find the always correct statement?
For example 1=1 , 1 = 1, ''=''

Answer 1

([^,\s]+?)\s?=\s?\1
only full match I don't know the go
language for functions, but something like this: 1) Divide into groups (?P[^,\s]+ ?)\s?=\s?(?P[^,\s]+) 2) Get the group ${a} and the group ${b} for comparison

str := "1=1, 1=2, 1 = 1, '' = '', 3 = f"
reg := regexp.MustCompile("(?P<a>[^,\s]+?)\s?=\s?(?P<b>[^,\s]+)")
match := reg.FindAllString(str, -1)

probably such a beginning, then in match there should be groups ${a} and ${b} and they need to be taken out and compared in turn, I don’t know the backend, but you can’t write on pure regular expressions in Go .

Answer 2

enumeration