How to extract a link from a Selenium WebElement?

Question

Python

when I do

webdriver.ActionChains(driver).move_to_element(my_link).click(my_link).perform()

then an error is thrown

selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable: https://www.verandaresort.com/contact.html has no size and location
  (Session info: chrome=90.0.4430.72)

in general, I don’t need to click on this element, but it’s enough to get a link (which just drops out in an error)

how to convert Selenium WebElement into just a link like in an error?

Answer 1

url = my_link.get_attribute('href')