How to execute a function after return in python?

Question

Django

Hello, I am writing a bot for VK in Python (Django)
The problem is that

In response to each event notification, your server should send an "ok" string.

The code can run for more than 1 minute (the report is generated from different sources).
VK throws new requests and duplicate messages come.
Is there any way to send "OK" to the server and continue generating the report. The user is then notified (wait 1 minute..)
return HttpResponse('ok')

Answer 1

Use something like Celery .

Answer 2

Nobody prevents you from running your processing in a separate thread.