How to exclude folder from gulp-imagemin processing?

Question

JavaScript

The question is in the title. The method given below leads to the fact that in general all images are not processed. I created an issue on github, the author sent it to stackoverflow.

gulp.task('default', function () {
    return gulp.src(['src/images/**', '!src/images/sprites/**'])
        .pipe(imagemin())
        .pipe(gulp.dest('dist'));
});

Answer 1

What version is being used?
Try again like this

gulp.task('default', function () {
    return gulp.src(['./src/images/**/*', '!./src/images/sprites/**/*'])
        .pipe(imagemin())
        .pipe(gulp.dest('./dist/images'));
});

I also recommend using gulp-cache with imagemin

Answer 2

Try looking away: gulp-ignore