How to exclude all contents of a directory in gulp.src but leave .htaccess in it?

Question

gulp.js

It is necessary to exclude the contents of the cache folder in the build task, leaving only the .htaccess file in it.
Task content:

gulp.task('build', gulp.series('clean', function () {
    return gulp.src([
        "app/**/*",
        "!app/cache/**/*",
        "app/cache/.htaccess",
    ], {allowEmpty: true, dot: true})   
        .pipe(gulp.dest('dist'));
}));

It turns out to either save all the content, including the unnecessary cache, or only an empty folder remains without the .htaccess file.
Tried many options, nothing works. Please tell me how to exclude this file.