How to escape regex in bash script for sed?

Question

bash

It is required to replace all found occurrences by regular expression with :url()
Regular

/[:,\s]\s*url\s*\(\s*(?:'(\S*?)'|"(\S*?)"|((?:\\\s|\\\)|\\"|\\'|\S)*?))\s*\)/gi

General form:

npm run bla-bla-bla | sed -r "s/[:,\s]\s*url\s*\(\s*(?:'(\S*?)'|\"(\S*?)\"|((?:\\\s|\\\)|\\\"|\\'|\S)*?))\s*\)/:url()/gi" > file.css

I ran into a problem - I can’t screen everything correctly, then I spoil the regular season itself, or something else. Maybe such a complex regex needs awk?
Thank you.

Answer 1

Wrap the regular expression in $'...' with single quote escaping:

npm run bla-bla-bla | sed -r $'"s/[:,\s]\s*url\s*\(\s*(?:'(\S*?)'|\"(\S*?)\"|((?:\\\s|\\\)|\\\"|\\'|\S)*?))\s*\)/:url()/gi"' > file.css