How to display the result of processing an image in Django?

Question

Django

I have an Image class that looks like this:

class Image(models.Model):
    title = models.TextField()
    file = models.ImageField(upload_to='images/')

    def __str__(self):
        return self.title

    def recognise(self):
        im = cv2.imread(self.file.path)
        preprocess = "thresh"
        gray = cv2.cvtColor(im, cv2.COLOR_BGR2GRAY)
        if preprocess == "thresh":
            gray = cv2.threshold(gray, 0, 255,
                                 cv2.THRESH_BINARY | cv2.THRESH_OTSU)[1]
        elif preprocess == "blur":
            gray = cv2.medianBlur(gray, 3)
        filename = "urui.png"
        cv2.imwrite(filename, gray)
        pytesseract.pytesseract.tesseract_cmd = r'C:\Program Files (x86)\Tesseract-OCR\tesseract.exe'
        return pytesseract.image_to_string(Image.open(filename), lang='rus')

It is used when the user uploads an image on the site. Accordingly, the file is saved. And then I need to process it and display the result on the screen. How can I do that? I don’t quite understand where to prescribe what in views. I understand that recognize should be applied to the file, but where?