How to display the received camera in html page?

Question

Django

Hello. I need to display a stream on a page. Here is the code:
views.py:

class VideoCamera(object):
    def __init__(self):
        self.video = cv2.VideoCapture('rtsp://x.x.x.x:554/user=x&password=x&channel=1&stream=0.sdp?real_stream--rtp-caching=100')
        (self.grabbed, self.frame) = self.video.read()
        threading.Thread(target=self.update, args=()).start()

    def __del__(self):
        self.video.release()

    def get_frame(self):
        image = self.frame
        ret, jpeg = cv2.imencode('.jpg', image)
        return jpeg.tobytes()

    def update(self):
        while True:
            (self.grabbed, self.frame) = self.video.read()


cam = VideoCamera()


def gen(camera):
    while True:
        frame = cam.get_frame()
        yield(b'--frame\r\n'
              b'Content-Type: image/jpeg\r\n\r\n' + frame + b'\r\n\r\n')


def livefe(request):
    try:
        return StreamingHttpResponse(gen(VideoCamera()), content_type="multipart/x-mixed-replace;boundary=frame")
    except:  # This is bad! replace it with proper handling
        pass

How to display a stream on a page? What should be written in urls.py and in html itself ?