How to display the number of array elements greater than a given number?

Question

Java

the whole essence of the task, here:
Create class MyTestMethod with generic static method calcNum (with two parameters: an array T[] and variable maxElem of type T) that counts the number of elements in an array T[] that are greater than a specified element maxElem.

That is, how to search for the maximum number in the code, I understand:

double max = arra[0];
        for (int i = 0; i < arra.length; i++) {
            if (arra[i] > max)
             max = arra[i];
        }
        System.out.println("Max is " + max);

and the fact that using length you can determine the length of the array, this is understandable, it’s simple, but here’s how to use the knowledge of the maximum number to search through the array, displaying all the numbers after, I don’t understand, when you try to sketch out the code, you get something crazy , type:

public static <T> int calcNum(T[] array, T maxElem) {
        int count = 0;
        for (int i = 0; i < array.length; i++) {
            for (int j = i; j < array.length; j++) {
                System.out.println((array[i, j]);
            }
        }

Thank you for your attention

Answer 1

Here's what Google translate says about it:

Create a class MyTestMethod with a generic static method calcNum (with two parameters: an array T[] and a variable maxElem of type T) that counts the number of elements in the array T[] greater than the specified maxElem.

Everything becomes clear immediately:

static <T extends Comparable<T>> int calcNum(T[] array, T maxElem) {
   int count = 0;
   // Тривиальная реализация подсчета количества элементов, больших чем maxElem.
   return count;
}