How to determine the probability of two coefficients?

Question

Mathematics

If team A has X past win odds (eg: 2.5)
If team B has Y past win odds (eg: 3.7)
How do you get the probability (between 0 and 1) that A wins?

Answer 1

No way.
The team "Arkharovtsi" from Nizhny Kukuev has a past win rate of 10.
The team "Atletico" from Madrid has a past win rate of 8.
What are the chances of Arkharovtsy winning?

Answer 2

past win rate

What it is?
Let it be the ratio of wins to losses. Then the probability of winning will be R = x/(x+1).
For your case Rx=71%, Ry=79%.
It is logical that the second team has a great chance of winning (as much as 8%).
Let us calculate the probabilities of winning teams in the match Px=Rx(1-Ry)=16%, Py=23%.
The question arises: where did the remaining 39% go? Unclear. I don't know.

Answer 3

In general, no way.
The first reason was pointed out here: perhaps they had different opponents.
The second reason: it happens that the system is arranged as "rock-paper-scissors", i.e. if team A won against team X and team B lost against team X, then it does not follow that team A will win against team B.