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How to determine the location of the taskbar (bottom, left, etc.) and its size in Windows?
Bottom line: I want the application window to be displayed approximately at the same place as the start menu in Windows (xp, vista, 7). My logic is this: knowing the screen resolution and taskbar settings, with the help of simple calculations, you can place the window in the appropriate area.
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Dimension screenSize = Toolkit.getDefaultToolkit().getScreenSize();
Insets scnMax = Toolkit.getDefaultToolkit().getScreenInsets(getGraphicsConfiguration());
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