How to determine the desired response from php json_encode in jq?

Question

PHP

in php, when all checks passed successfully, try to send response

echo json_encode(array("success" => $result, "pagi" => $pagi), JSON_UNESCAPED_UNICODE);

That is, give an array of $result and $pagi

to jq

$.ajax({
url: '...',
type: 'post',
dataType: 'json',
data: ...,
success: function(json){

if(typeof json.success !== 'undefined'){

$(document).find('.loadItemsHere').html(json.success);
}

else if(typeof json.error !== 'undefined'){
alert(json.error);
} 

else if(typeof json.pagi !== 'undefined'){

$(document).find('.loadItemsHere').after(json.pagi);
}

}, error: ....

If output separately

echo json_encode(["success" => $result], JSON_UNESCAPED_UNICODE);

or

echo json_encode(["pagi" => $pagi], JSON_UNESCAPED_UNICODE);

Then everything comes as it should, but passing two parameters only success comes

Answer 1

if(typeof json.success !== 'undefined'){
  $(document).find('.loadItemsHere').html(json.success);
}
else if

You receive all the parameters, but only one is displayed, because the code is not executed beyond this condition!