How to create a copy of a list that only contains elements that meet a condition?

Question

Python

Original :
["11", "2", "3", "4", "55"]
condition: len(element) > 1
Copy would be:
["11", "55"]

Is it possible to do this without loops? Are there built-in solutions?

Answer 1

>>> lst = ["11", "2", "3", "4", "55"]
>>> new_lst = filter(lambda x: len(x) > 1, lst)
>>> new_lst
['11', '55']

Answer 2

original = ["11", "2", "3", "4", "55"]
new = [el for el in original if len(el) > 1]