How to correctly write elements from the RQ queue to the list?

Question

Python

I work with workers and queue

from rq import Queue
from redis import Redis


import time



redis_conn = Redis()
queue = Queue(connection=redis_conn)

list_int = []

def worker(num, timeout):
    time.sleep(timeout)
    list_int.append(num)

    return num

the problem is that when the worker gets queued, it contains a reference to an empty list
And if we start the workers with a frequency of 1 second, and they are given a timeout of 5 seconds, then they overwrite the list
That is, the elements are not added to the end of the list , but a list with one element is created
. I still don’t really understand how to solve this.
If someone has thoughts, I will be very grateful)

ZY . I forgot to show how it gets in line at all

from fastapi import FastAPI
@app.get("/api/{num}/{timeout}")
def read_root(num: int, timeout: int):
    job = queue.enqueue(worker, num, timeout)
    return {"Task": "in work"}

Answer 1

Why use a global variable?