How to correctly pass a parameter in Django to url?

Question

Django

I'm using the slug model to navigate to articles via titles in the address bar. I wrote everything in the URL as in the documentation:

urlpatterns = patterns('content.views',
    url(r'^publication/add/', 'add_publication', name = 'Add_publication'),
    url(r'^publication/(?P<slug>[a-z0-9_-]+)/$', 'get_publication', name = 'Get_publication'),
    url(r'^publication/edit/(?P<slug>[a-z0-9_-]+)/$', 'edit_publication', name = 'Edit_publication'),

The problem is that when I pass the parameter in the url like this:

<a href="{% url 'Edit_publication' publication.slug %}" class="btn btn-warning">Редактировать новость</a>

Error:
NoReverseMatch
Reverse for 'Edit_publication' with arguments '('text-2',)' and keyword arguments '{}' not found. 0 pattern(s) tried: []
If I write like this:

<a href="/publication/edit/{{ publication.slug }}" class="btn btn-warning">Редактировать новость</a>

then everything works without problems, but it’s wrong to do this throughout the site, as you understand. Can you explain what is the problem? I will add that I have tried methods like "{% url 'content:edit_publication' publication.slug %}" or "{% url 'Edit_publication' slug=publication.slug %}" but it does not help. I think it makes no sense to throw off View, because the parameters, based on the second method, accept and work without problems.

Answer 1

Urls included in main urls.py?

Answer 2

{% url 'Edit_publication' slug=publication.slug %}
What outputs? slug is empty?