How to correctly generate a URL using jQuery?

Question

JavaScript

The page has pagination, it works correctly without filters.
If filters are applied, a huge URL is formed and pagination stops working.

function toggleDom(dom) {
    //если включен - выключим
    if ($("#for_number" + dom).hasClass('active')){
        $("#for_number" + dom).removeClass('active');
        $("#Kvartiry_doma_" + dom).val(0);
    }
    else{
        $("#for_number" + dom).addClass('active');	
        $("#Kvartiry_doma_" + dom).val(1);
    }
}

One of the filter buttons on the form:

<a  id="for_number1a" 
 class="dom_number<?= $model->doma['1a'] ? ' active' : '' ?>" 
onclick="toggleDom('1a'); return false;">1А
</a>

received
URL http://mysite/kvartiry?Kvartiry_page=3&Kvartiry_p...

How to fix the JS code so as not to damage the pagination when using the filter and at the same time fix the url?

Answer 1

Convenient JQuery lib for working with Query Params:
https://github.com/alrusdi/jquery-plugin-query-object