How to copy needed files via gulp?

Question

JavaScript

Why is my public folder deleted on first launch? After restart everything is ok.
How to write in this line

return gulp.src('frontend/assets/{fonts,images}/**', {since: gulp.lastRun('assets')})

so that not only the fonts, images folders would be copied, but also the index.html file for example?
My settings:

const gulp = require('gulp');
const concatCSS = require('gulp-concat-css');
const debug = require('gulp-debug');
const sourcemaps = require('gulp-sourcemaps');
const gulpIf = require('gulp-if');
const del = require('del');

const isDevelopment = !process.env.NODE_ENV || process.env.NODE_ENV == 'development';

gulp.task('styles', function () {

  return gulp.src('frontend/**/*.css')
    .pipe(concatCSS('all.css'))
    .pipe(gulpIf(isDevelopment, sourcemaps.init()))
    .pipe(gulpIf(isDevelopment, sourcemaps.write()))
    .pipe(gulp.dest('public'));

});

gulp.task('clean', function() {
  return del('public');
});

gulp.task('assets', function() {
  return gulp.src('frontend/assets/{fonts,images}/**', {since: gulp.lastRun('assets')})
    .pipe(gulp.dest('public'));
});

gulp.task('build', gulp.series(
  'clean',
  gulp.parallel('styles', 'assets'))
);

gulp.task('watch', function() {
  gulp.watch('frontend/styles/**/*.*', gulp.series('styles'));
  gulp.watch('frontend/assets/**/*.*', gulp.series('assets'));
});

gulp.task('dev', gulp.series('build', 'watch'));

Answer 1

the folder is deleted because

gulp.task('clean', function() {
  return del('public');
});

write down

return gulp.src(['frontend/assets/{fonts,images}/**', 'frontend/assets/index.html'], {since: gulp.lastRun('assets')})