How to convert request request from PHP to Java (under Android)?

Question

PHP

In general, I have never worked with php, but there is a request, it seems to be simple, but I don’t know how to implement it in android studio, maybe through a post request?

$ip = '80.82.45.226';      //Ваш ip адрес
            $port = 8089;           //Ваш порт
            $secret = 'llksdjhKJHKJjhjdaf';     //Ваш секретный ключ
        //  $crew_group_id = 59;    //Группа экипажей

            function autoloader($classname) {
                $dir = dirname(__FILE__);
                if(strpos($classname, 'Request') !== false) {
                    include $dir . '/Request/' . $classname . '.php'; //Указать правильную папку!
                } else if (strpos($classname, 'Response') !== false) {
                    include $dir . '/Response/' . $classname . '.php'; //Указать правильную папку!
                }
            }

            spl_autoload_register('autoloader');


            $request = new CreateOrderRequest($ip, $port, $secret);

            $request
                ->setPhone($_POST["Number"])
                ->setCustomer($_POST["OrderClientName"])
                ->setSource($_POST["OrderSourceAddress"])
                ->setDest($_POST["OrderDestAddress"])
                ->setComment($_POST["OrderComment"])
                ->setCrewGroupId($_POST["СrewGroupId"])
                ;

            $request->send();

Answer 1

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;

public class HttpSend {
  public static void main(String[] args) {
    System.out.println(SendJsonViaPost("http://toster.ru/", "ваш json"));
  }

  public static String SendJsonViaPost(String url, String json) {
    String responseJson = "";
    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost(url);
    try {
      StringEntity stringEntity = new StringEntity(json, "UTF-8");
      stringEntity.setContentType("application/json");
      post.setEntity(stringEntity);
      HttpResponse response = client.execute(post);
      BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
      String line = "";
      while ((line = rd.readLine()) != null) {
        responseJson += line;
      }
      
    } catch (IOException e) {
      e.printStackTrace();
    }
    
    return responseJson;
  }
}

HttpSend.sendJsonViaPost("http://toster.ru/", "ваш json")

Answer 2

How to convert request request from PHP to Java (under Android)?

in fact, nothing, only if your device has a dedicated IP.
The code given by you as I understand for MundiPagg? Then as I understand you need to make a request to their server.
In general, try to figure out what you need to do, but how - these are already trifles.

Answer 3

public void postData() {
    // Создадим HttpClient и PostHandler
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.moisaitik.ru/postdemo.php");

    try {
        // Добавим данные (пара - "название - значение")
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("login", "andro"));
        nameValuePairs.add(new BasicNameValuePair("text", "Привет!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Выполним запрос
        HttpResponse response = httpclient.execute(httppost);
        
    } catch (ClientProtocolException e) {
        // Ошибка :(
    } catch (IOException e) {
        // Ошибка :(
    }
}

1 of the examples from a google query. It's not clear from your code where the secret goes. You need to look at the class constructor. Most likely in the header.