How to convert from decimal to binary with a certain number of characters?

Question

Python

I know that there is a bin() function, is it possible to somehow specify the number of characters, let's say bin(3) will make 11, but I need 0011, can there be any analogue?

Answer 1

zfill will save a young programmer

>>> bin(777)[2:].zfill(22)
'0000000000001100001001'

although I would just use format

>>> format(777, '022b')
'0000000000001100001001'

Answer 2

Format the resulting string .

s1 = bin(3) #0b11
s2 = s1[2:] #11
s3 = '{0:>04s}'.format(s2) #0011
print(s3)
# ну или в одну строку
print('{0:>04s}'.format(bin(3)[2:]))