How to concisely rewrite code in python?

Question

Python

text to be parsed:

from pyparsing import *

texta = '''<RDF:RDF xmlns:NS1="http://amb.vis.ne.jp/mozilla/scrapbook-rdf#"
         xmlns:NC="http://home.netscape.com/NC-rdf#"
         xmlns:RDF="http://www.w3.org/1999/02/22-rdf-syntax-ns#">
  <RDF:Description RDF:about="urn:scrapbook:item20200711150730"
                   NS1:id="20200711150730"
                   NS1:create="20200711150730"
                   NS1:title="Делаем из Vim-а конфетку / Хабр"
                   NS1:chars="UTF-8"
                   NS1:source="https://habr.com/ru/post/468265/"
                   NS1:comment=""
                   NS1:lock=""
                   NS1:type=""
                   NS1:icon="resource://scrapbook/data/20200711150730/favicon-16x16.png"
                   NS1:modify="20200711150804" />
  <RDF:Seq RDF:about="urn:scrapbook:item20200704081851">
    <RDF:li RDF:resource="urn:scrapbook:item20200704081900"/>
    <RDF:li RDF:resource="urn:scrapbook:item20200711150730"/>
  </RDF:Seq>'''

parser code:

ns_id_p = Literal("NS1:id=")
pars = ns_id_p + Suppress('"') + Word(nums) + Suppress('"')
xx = pars.searchString(texta)
xxx = xx[0]
yyy = xxx[1]
print('xx ', xx)
print('xxx ', xxx)
print('yyy ', yyy)

conclusion:

xx  
xxx  ['NS1:id=', '20200711150730']
yyy  20200711150730

how to get the value of yyy more concisely in python style

Answer 1

Conciseness should not be an end in itself. And then, what do you mean - "succinctly"? Fewer lines of code? Less characters?
You can write - if the question is "how to get the value of yyy" - like this:

print('yyy ', (Literal("NS1:id=") + Suppress('"') + Word(nums) + Suppress('"')).searchString(texta)[0][1])

Laconically. That's just exactly at least worse readable.

Answer 2

Looking what task and what restrictions. If you're just looking for strings like
NS1:id="numbers",
then regular expressions will do. For example, re.compile('NS1:id="(\d+)"').
But if you then need to work with the structure of the xml document, then you need to use lxml.ElementTree.