How to concatenate JS and wrap it in $(document).ready()?

Question

JavaScript

I want to split my code into subfiles with the implementation of different page elements in them. jQuery is needed to execute each such code.
the question is how to store all this in different files, and concatenate into one?

Answer 1

Can be done via gulp-include

jQuery(document).ready(function($) {
    //=include include/_header.js
    //=include include/_slider.js
    //=include include/_shop.js
    //=include include/_range.js
    //=include include/_tabs.js
});

Answer 2

https://learn.javascript.ru/modules

Answer 3

I have a similar question. What is the correct way to use jQuery with gulp-conact? How did you decide?