How to compare numbers modulo in bash?

Question

bash

There are 2 numbers. There may be a slight difference between these numbers. I want to compare these numbers with tolerance. Let's say 10 and 13 have a tolerance of 5. "10 - 13 = -3" should look like "-3" is less than "5" in absolute value. I don't know if it's possible to look at numbers modulo in bash? Can bc do this or is it somehow possible?

Answer 1

Try
${VAR#-}

Answer 2

expand the module into two conditions.

Answer 3

No, in my opinion, the Bash module is not able to take. But the square can:

$ a=10
$ b=13
$ delta=5
$ (((a-b)**2 <= delta**2)) && echo 'OK'