How to compare each element in a Python list?

Question

Python

Hello! Let's say I have a python list like this:
a = [1, 2, 3]
I need to find out if each element is greater than the previous one. How can I implement this?

Answer 1

Read help(all) or help(any)

>>> l=[1,2,3]
>>> all(l[i] < l[i+1] for i in range(len(l)-1))
True
>>> l=[3,2,1]
>>> all(l[i] < l[i+1] for i in range(len(l)-1))
False

Answer 2

Hey!
If each element is greater than the previous one, you will de facto have a sorted list. Therefore, just compare your current one with the sorted one. If True - everything is fine, each element is greater than the previous one, otherwise - False :

>>> new_list = [1, 2, 3, 4, 5, 6]
>>> new_list == sorted(new_list)
True
>>> new_list = [1, 2, 3, 4, 8, 6, 5]
>>> new_list == sorted(new_list)
False

Answer 3

In the loop, compare "a[i]" with "a[i+1]" while i is less than the length of the array - 1.
On each iteration i+1.