How to compare each digit in a number character by character?

Question

C++ / C#

Let's start with an example to understand what I mean. For example, there is a number 978560 and I want to compare each digit with each other and if the number on the left is less than on the right, then I swap them.
We go from the end of the number (6 < 0) (no), (5 < 6) (yes, we swap places) = 978650 and. etc.
How to implement this?

Answer 1

Calculate the remainder after dividing by 10. Get an array of digits from the end. Well, then compare neighbors and swap

Answer 2

translate the number into a string,
the string is an array of charms ,
drive the array with any algorithms

Answer 3

Support: you can easily convert a number to a string (even with a dot) and work with it as with an array of single digits and separator characters. And the value of the number, again, can be obtained at any time from number[i]-'0' ('1' - '0' will be 1, '6'-'0' will be 6, etc.)

Answer 4

Book Algorithms "Kormen" second chapter. A simple sorting algorithm. Exactly what you need.
Not hard to find in pdf format. At the top of the search immediately.