How to check the correctness of the ip address in ruby?

Question

ruby

There is a function that receives an ip address as an argument like this: http://127.34.72.163:82/test
How can you easily check that by passing an argument it is a correct ip address?

Googling, I found that there is a native library that checks the correctness of the IP

require "resolv"

"192.168.1.1"   =~ Resolv::IPv4::Regex ? true : false #=> true
"192.168.1.500" =~ Resolv::IPv4::Regex ? true : false #=> false

"ff02::1"    =~ Resolv::IPv6::Regex ? true : false #=> true
"ff02::1::1" =~ Resolv::IPv6::Regex ? true : false #=> false

But the problem is that I still have ip http://at the beginning and /testafter it, and with this argument, the library no longer works correctly. Perhaps you can check it somehow easier with regular expressions, or something else?
Help a newbie understand how to solve this problem correctly?

Answer 1

require 'net/http'

def correctIpAddress?(source)
  begin
    url = URI.parse(source)
  rescue URI::InvalidURIError
    return false
  rescue StandardError
    raise
  end

  host = url.host

  begin
    ip = IPAddr.new host
  rescue IPAddr::InvalidAddressError
    return false
  rescue StandardError
    raise
  end

  return true
end

puts correctIpAddress?('https://example.com/foo') # valid url, no ip address
puts correctIpAddress?('foo bar 42 $%$%') # invalid url
puts correctIpAddress?('https://127.0.0.1/foo') # valid url, valid ip address

Answer 2

The above address is incorrect. This is a url, so take a library to check the url, get the host, check it with a regexp for the condition that each part is less than 256 and already accumulate this line to the ip parser. Or immediately do a regexp, isolate the numbers separated by 3 dots and give this result to your library for verification