How to catch various rejects in a promise and break the chain?

Question

JavaScript

Please tell me, I'm confused.
Suppose there is some function that returns various states. One state - everything is ok, and different views when something went wrong. You need to run the handler for this state and exit the chain.

function p1(inputData) {
    return new Promise((resolve, reject) => {
        switch(inputData) {
           case SUCCESS_0:
              resolve("Success 0");
              break;
           case ERROR_0:
              reject("Reason 0");
              break;
           case ERROR_1:
              reject("Reason 1");
              break;
           case ERROR_2:
              reject("Reason 2");
              break;
        }
        });
}

you need something like output

p1(inputData)
    .catch(ERROR_0, () => processError_0()) //и выйти из цепочки
    .catch(ERROR_1, () => processError_1()) //и выйти из цепочки
    .catch(ERROR_2, () => processError_2()) //и выйти из цепочки
    .then(ifSuccess_0());  //только если не вылезла ошибка в p1

How can it be gracefully written so that the code works and reads normally?

Answer 1

then move to the beginning of the chain, well, on codepen an example of incomprehensible code